S=2x^2-20x+112

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Solution for S=2x^2-20x+112 equation: 



=2S^2-20S+112

We move all terms to the left:

-(2S^2-20S+112)=0

We get rid of parentheses

-2S^2+20S-112=0

a = -2; b = 20; c = -112;
Δ = b2-4ac
Δ = 202-4·(-2)·(-112)
Δ = -496
Delta is less than zero, so there is no solution for the equation

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